Optimal. Leaf size=220 \[ -\frac {5 b \tanh ^{-1}\left (\frac {2 a+\frac {b}{x}}{2 \sqrt {a} \sqrt {a+\frac {b}{x}+\frac {c}{x^2}}}\right )}{2 a^{7/2}}-\frac {2 x \left (32 a^2 c^2+\frac {b c \left (5 b^2-28 a c\right )}{x}-32 a b^2 c+5 b^4\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+\frac {b}{x}+\frac {c}{x^2}}}+\frac {x \left (128 a^2 c^2-100 a b^2 c+15 b^4\right ) \sqrt {a+\frac {b}{x}+\frac {c}{x^2}}}{3 a^3 \left (b^2-4 a c\right )^2}-\frac {2 x \left (-2 a c+b^2+\frac {b c}{x}\right )}{3 a \left (b^2-4 a c\right ) \left (a+\frac {b}{x}+\frac {c}{x^2}\right )^{3/2}} \]
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Rubi [A] time = 0.19, antiderivative size = 220, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {1342, 740, 822, 806, 724, 206} \[ -\frac {2 x \left (32 a^2 c^2+\frac {b c \left (5 b^2-28 a c\right )}{x}-32 a b^2 c+5 b^4\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+\frac {b}{x}+\frac {c}{x^2}}}+\frac {x \left (128 a^2 c^2-100 a b^2 c+15 b^4\right ) \sqrt {a+\frac {b}{x}+\frac {c}{x^2}}}{3 a^3 \left (b^2-4 a c\right )^2}-\frac {5 b \tanh ^{-1}\left (\frac {2 a+\frac {b}{x}}{2 \sqrt {a} \sqrt {a+\frac {b}{x}+\frac {c}{x^2}}}\right )}{2 a^{7/2}}-\frac {2 x \left (-2 a c+b^2+\frac {b c}{x}\right )}{3 a \left (b^2-4 a c\right ) \left (a+\frac {b}{x}+\frac {c}{x^2}\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 206
Rule 724
Rule 740
Rule 806
Rule 822
Rule 1342
Rubi steps
\begin {align*} \int \frac {1}{\left (a+\frac {c}{x^2}+\frac {b}{x}\right )^{5/2}} \, dx &=-\operatorname {Subst}\left (\int \frac {1}{x^2 \left (a+b x+c x^2\right )^{5/2}} \, dx,x,\frac {1}{x}\right )\\ &=-\frac {2 \left (b^2-2 a c+\frac {b c}{x}\right ) x}{3 a \left (b^2-4 a c\right ) \left (a+\frac {c}{x^2}+\frac {b}{x}\right )^{3/2}}+\frac {2 \operatorname {Subst}\left (\int \frac {\frac {1}{2} \left (-5 b^2+16 a c\right )-3 b c x}{x^2 \left (a+b x+c x^2\right )^{3/2}} \, dx,x,\frac {1}{x}\right )}{3 a \left (b^2-4 a c\right )}\\ &=-\frac {2 \left (b^2-2 a c+\frac {b c}{x}\right ) x}{3 a \left (b^2-4 a c\right ) \left (a+\frac {c}{x^2}+\frac {b}{x}\right )^{3/2}}-\frac {2 \left (5 b^4-32 a b^2 c+32 a^2 c^2+\frac {b c \left (5 b^2-28 a c\right )}{x}\right ) x}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+\frac {c}{x^2}+\frac {b}{x}}}-\frac {4 \operatorname {Subst}\left (\int \frac {\frac {1}{4} \left (15 b^4-100 a b^2 c+128 a^2 c^2\right )+\frac {1}{2} b c \left (5 b^2-28 a c\right ) x}{x^2 \sqrt {a+b x+c x^2}} \, dx,x,\frac {1}{x}\right )}{3 a^2 \left (b^2-4 a c\right )^2}\\ &=\frac {\left (15 b^4-100 a b^2 c+128 a^2 c^2\right ) \sqrt {a+\frac {c}{x^2}+\frac {b}{x}} x}{3 a^3 \left (b^2-4 a c\right )^2}-\frac {2 \left (b^2-2 a c+\frac {b c}{x}\right ) x}{3 a \left (b^2-4 a c\right ) \left (a+\frac {c}{x^2}+\frac {b}{x}\right )^{3/2}}-\frac {2 \left (5 b^4-32 a b^2 c+32 a^2 c^2+\frac {b c \left (5 b^2-28 a c\right )}{x}\right ) x}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+\frac {c}{x^2}+\frac {b}{x}}}+\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {a+b x+c x^2}} \, dx,x,\frac {1}{x}\right )}{2 a^3}\\ &=\frac {\left (15 b^4-100 a b^2 c+128 a^2 c^2\right ) \sqrt {a+\frac {c}{x^2}+\frac {b}{x}} x}{3 a^3 \left (b^2-4 a c\right )^2}-\frac {2 \left (b^2-2 a c+\frac {b c}{x}\right ) x}{3 a \left (b^2-4 a c\right ) \left (a+\frac {c}{x^2}+\frac {b}{x}\right )^{3/2}}-\frac {2 \left (5 b^4-32 a b^2 c+32 a^2 c^2+\frac {b c \left (5 b^2-28 a c\right )}{x}\right ) x}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+\frac {c}{x^2}+\frac {b}{x}}}-\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{4 a-x^2} \, dx,x,\frac {2 a+\frac {b}{x}}{\sqrt {a+\frac {c}{x^2}+\frac {b}{x}}}\right )}{a^3}\\ &=\frac {\left (15 b^4-100 a b^2 c+128 a^2 c^2\right ) \sqrt {a+\frac {c}{x^2}+\frac {b}{x}} x}{3 a^3 \left (b^2-4 a c\right )^2}-\frac {2 \left (b^2-2 a c+\frac {b c}{x}\right ) x}{3 a \left (b^2-4 a c\right ) \left (a+\frac {c}{x^2}+\frac {b}{x}\right )^{3/2}}-\frac {2 \left (5 b^4-32 a b^2 c+32 a^2 c^2+\frac {b c \left (5 b^2-28 a c\right )}{x}\right ) x}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+\frac {c}{x^2}+\frac {b}{x}}}-\frac {5 b \tanh ^{-1}\left (\frac {2 a+\frac {b}{x}}{2 \sqrt {a} \sqrt {a+\frac {c}{x^2}+\frac {b}{x}}}\right )}{2 a^{7/2}}\\ \end {align*}
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Mathematica [A] time = 0.38, size = 256, normalized size = 1.16 \[ \frac {2 \sqrt {a} \left (3 b^4 \left (a^2 x^4-30 a c x^2+5 c^2\right )-4 a b^2 c \left (6 a^2 x^4-12 a c x^2+25 c^2\right )+8 a^2 b c^2 x \left (32 a x^2+39 c\right )+16 a^2 c^2 \left (3 a^2 x^4+12 a c x^2+8 c^2\right )+10 b^5 \left (2 a x^3+3 c x\right )-2 a b^3 c x \left (74 a x^2+105 c\right )+15 b^6 x^2\right )-15 b \left (b^2-4 a c\right )^2 (x (a x+b)+c)^{3/2} \tanh ^{-1}\left (\frac {2 a x+b}{2 \sqrt {a} \sqrt {x (a x+b)+c}}\right )}{6 a^{7/2} x \left (b^2-4 a c\right )^2 (x (a x+b)+c) \sqrt {a+\frac {b x+c}{x^2}}} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.45, size = 1081, normalized size = 4.91 \[ \left [\frac {15 \, {\left (b^{5} c^{2} - 8 \, a b^{3} c^{3} + 16 \, a^{2} b c^{4} + {\left (a^{2} b^{5} - 8 \, a^{3} b^{3} c + 16 \, a^{4} b c^{2}\right )} x^{4} + 2 \, {\left (a b^{6} - 8 \, a^{2} b^{4} c + 16 \, a^{3} b^{2} c^{2}\right )} x^{3} + {\left (b^{7} - 6 \, a b^{5} c + 32 \, a^{3} b c^{3}\right )} x^{2} + 2 \, {\left (b^{6} c - 8 \, a b^{4} c^{2} + 16 \, a^{2} b^{2} c^{3}\right )} x\right )} \sqrt {a} \log \left (-8 \, a^{2} x^{2} - 8 \, a b x - b^{2} - 4 \, a c + 4 \, {\left (2 \, a x^{2} + b x\right )} \sqrt {a} \sqrt {\frac {a x^{2} + b x + c}{x^{2}}}\right ) + 4 \, {\left (3 \, {\left (a^{3} b^{4} - 8 \, a^{4} b^{2} c + 16 \, a^{5} c^{2}\right )} x^{5} + 4 \, {\left (5 \, a^{2} b^{5} - 37 \, a^{3} b^{3} c + 64 \, a^{4} b c^{2}\right )} x^{4} + 3 \, {\left (5 \, a b^{6} - 30 \, a^{2} b^{4} c + 16 \, a^{3} b^{2} c^{2} + 64 \, a^{4} c^{3}\right )} x^{3} + 6 \, {\left (5 \, a b^{5} c - 35 \, a^{2} b^{3} c^{2} + 52 \, a^{3} b c^{3}\right )} x^{2} + {\left (15 \, a b^{4} c^{2} - 100 \, a^{2} b^{2} c^{3} + 128 \, a^{3} c^{4}\right )} x\right )} \sqrt {\frac {a x^{2} + b x + c}{x^{2}}}}{12 \, {\left (a^{4} b^{4} c^{2} - 8 \, a^{5} b^{2} c^{3} + 16 \, a^{6} c^{4} + {\left (a^{6} b^{4} - 8 \, a^{7} b^{2} c + 16 \, a^{8} c^{2}\right )} x^{4} + 2 \, {\left (a^{5} b^{5} - 8 \, a^{6} b^{3} c + 16 \, a^{7} b c^{2}\right )} x^{3} + {\left (a^{4} b^{6} - 6 \, a^{5} b^{4} c + 32 \, a^{7} c^{3}\right )} x^{2} + 2 \, {\left (a^{4} b^{5} c - 8 \, a^{5} b^{3} c^{2} + 16 \, a^{6} b c^{3}\right )} x\right )}}, \frac {15 \, {\left (b^{5} c^{2} - 8 \, a b^{3} c^{3} + 16 \, a^{2} b c^{4} + {\left (a^{2} b^{5} - 8 \, a^{3} b^{3} c + 16 \, a^{4} b c^{2}\right )} x^{4} + 2 \, {\left (a b^{6} - 8 \, a^{2} b^{4} c + 16 \, a^{3} b^{2} c^{2}\right )} x^{3} + {\left (b^{7} - 6 \, a b^{5} c + 32 \, a^{3} b c^{3}\right )} x^{2} + 2 \, {\left (b^{6} c - 8 \, a b^{4} c^{2} + 16 \, a^{2} b^{2} c^{3}\right )} x\right )} \sqrt {-a} \arctan \left (\frac {{\left (2 \, a x^{2} + b x\right )} \sqrt {-a} \sqrt {\frac {a x^{2} + b x + c}{x^{2}}}}{2 \, {\left (a^{2} x^{2} + a b x + a c\right )}}\right ) + 2 \, {\left (3 \, {\left (a^{3} b^{4} - 8 \, a^{4} b^{2} c + 16 \, a^{5} c^{2}\right )} x^{5} + 4 \, {\left (5 \, a^{2} b^{5} - 37 \, a^{3} b^{3} c + 64 \, a^{4} b c^{2}\right )} x^{4} + 3 \, {\left (5 \, a b^{6} - 30 \, a^{2} b^{4} c + 16 \, a^{3} b^{2} c^{2} + 64 \, a^{4} c^{3}\right )} x^{3} + 6 \, {\left (5 \, a b^{5} c - 35 \, a^{2} b^{3} c^{2} + 52 \, a^{3} b c^{3}\right )} x^{2} + {\left (15 \, a b^{4} c^{2} - 100 \, a^{2} b^{2} c^{3} + 128 \, a^{3} c^{4}\right )} x\right )} \sqrt {\frac {a x^{2} + b x + c}{x^{2}}}}{6 \, {\left (a^{4} b^{4} c^{2} - 8 \, a^{5} b^{2} c^{3} + 16 \, a^{6} c^{4} + {\left (a^{6} b^{4} - 8 \, a^{7} b^{2} c + 16 \, a^{8} c^{2}\right )} x^{4} + 2 \, {\left (a^{5} b^{5} - 8 \, a^{6} b^{3} c + 16 \, a^{7} b c^{2}\right )} x^{3} + {\left (a^{4} b^{6} - 6 \, a^{5} b^{4} c + 32 \, a^{7} c^{3}\right )} x^{2} + 2 \, {\left (a^{4} b^{5} c - 8 \, a^{5} b^{3} c^{2} + 16 \, a^{6} b c^{3}\right )} x\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 376, normalized size = 1.71 \[ -\frac {\left (a \,x^{2}+b x +c \right ) \left (-96 a^{\frac {13}{2}} c^{2} x^{4}+48 a^{\frac {11}{2}} b^{2} c \,x^{4}-6 a^{\frac {9}{2}} b^{4} x^{4}-512 a^{\frac {11}{2}} b \,c^{2} x^{3}+296 a^{\frac {9}{2}} b^{3} c \,x^{3}-40 a^{\frac {7}{2}} b^{5} x^{3}-384 a^{\frac {11}{2}} c^{3} x^{2}-96 a^{\frac {9}{2}} b^{2} c^{2} x^{2}+180 a^{\frac {7}{2}} b^{4} c \,x^{2}-30 a^{\frac {5}{2}} b^{6} x^{2}-624 a^{\frac {9}{2}} b \,c^{3} x +420 a^{\frac {7}{2}} b^{3} c^{2} x -60 a^{\frac {5}{2}} b^{5} c x -256 a^{\frac {9}{2}} c^{4}+200 a^{\frac {7}{2}} b^{2} c^{3}-30 a^{\frac {5}{2}} b^{4} c^{2}+240 \left (a \,x^{2}+b x +c \right )^{\frac {3}{2}} a^{4} b \,c^{2} \ln \left (\frac {2 a x +b +2 \sqrt {a \,x^{2}+b x +c}\, \sqrt {a}}{2 \sqrt {a}}\right )-120 \left (a \,x^{2}+b x +c \right )^{\frac {3}{2}} a^{3} b^{3} c \ln \left (\frac {2 a x +b +2 \sqrt {a \,x^{2}+b x +c}\, \sqrt {a}}{2 \sqrt {a}}\right )+15 \left (a \,x^{2}+b x +c \right )^{\frac {3}{2}} a^{2} b^{5} \ln \left (\frac {2 a x +b +2 \sqrt {a \,x^{2}+b x +c}\, \sqrt {a}}{2 \sqrt {a}}\right )\right )}{6 \left (\frac {a \,x^{2}+b x +c}{x^{2}}\right )^{\frac {5}{2}} \left (4 a c -b^{2}\right )^{2} a^{\frac {11}{2}} x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (a + \frac {b}{x} + \frac {c}{x^{2}}\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{{\left (a+\frac {b}{x}+\frac {c}{x^2}\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (a + \frac {b}{x} + \frac {c}{x^{2}}\right )^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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